0 0
0 4 0
0 0 0 0
0 4 0
0 0
1
0 0*
0 1* 4
0 0 0 16
0 0 0
0 0
0
* indicates jumping of $\operatorname{Aut}^0$
its dimension takes on the values 0, 1
Still open.
- index
- 1
- $\dim\mathrm{H}^0(X,\omega_X^\vee)$
- 16
- $-\mathrm{K}_X$ very ample?
- yes
- $-\mathrm{K}_X$ basepoint free?
- yes
- hyperelliptic
- no
- trigonal
- no
This variety is rational.
This variety is stably rational.
The Weyl group associated to the KKMR decomposition is $\mathrm{A}_1$; see the Weyl-group table for sources and conventions.
This variety is the blowup of
- number of moduli
- 1
- Bott vanishing
- does not hold
| $\mathrm{Aut}^0(X)$ | $\dim\mathrm{Aut}^0(X)$ | number of moduli |
|---|---|---|
| $\mathbb{G}_{\mathrm{m}}$ | 1 | 0 |
| $0$ | 0 | 1 |
A full exceptional collection can be constructed using Orlov's blowup formula.
Fano 3-folds from homogeneous vector bundles over Grassmannians gives the following description(s):
- variety
- $ \mathbb{P}^1_1 \times \mathbb{P}^1_2 \times \mathbb{P}^1_3 \times \mathbb{P}^4$
- bundle
- $\Lambda(0,0,0,1) \oplus \mathcal{O}(1,0,1,1)$
See the big table for more information.
- general member is K‑stable but there exist members that are not
- general member is K‑polystable but there exist members that are not
- every member is K‑semistable
For this deformation family, every smooth member has coregularity 0.
The generic and uniform statements are due to Avilov–Loginov–Przyjalkowski; the existence of a smooth member of coregularity zero in every family is due to Zhakupov.
See coregularity for terminology.
For every K-polystable member, the Futaki invariant vanishes identically on the entire Kähler cone.
This is the computation of Sektnan–Tipler.